Civil Guruji Naapshala · Measurement Master Class
Class 1 · Unit Conversion

Meters and Feet — the two languages of a construction site

Drawings are issued in meters, while site conversations happen in feet. An engineer who can switch between both units instantly always stays in control. This class builds that skill step by step.

Digital Tape Available in every step

Drag the tape left or right — the reading under the red pointer updates in every unit.

READ HERE
1 ft + 0 m +
Millimeters
Centimeters
Meters
Feet (decimal)
Feet–Inches
Lesson 4 Steps

Step 1 — The Meter

The meter is the international standard (SI) unit of length. Every drawing, structural detail and estimate is prepared in meters and millimeters.

Master Relation
1 m = 100 cm = 1000 mm
1 cm = 10 mm
Drawings Use
mm
Working drawings are dimensioned in millimeters
01020 304050 607080 90100 cm ← 1 METER = 100 cm →
Where you see meters on site

Door width ≈ 1 m|Floor height ≈ 3 m|TMT bar = 12 m|Slab thickness = 125 mm|Plinth ≈ 450–600 mm

Converting within the metric system
ConversionRuleExample
m → cm× 1002 m = 200 cm
cm → m÷ 100250 cm = 2.5 m
m → mm× 10001.5 m = 1500 mm
mm → m÷ 10001250 mm = 1.25 m
cm → mm× 1012 cm = 120 mm
mm → cm÷ 10340 mm = 34 cm
Linked converter — m ↔ cm ↔ mm

Type in any box — the other two update instantly.

=
=
Practice Round — Metric only

250 cm = ? m

Step 2 — The Foot

The foot is the unit of everyday site conversation. Masons, contractors and property dealers all speak in feet: a "10 by 12 room", a "7-foot door".

Foot
1 ft = 12 in
Inch numbers repeat after every foot mark
Soot
1 in = 8 soot
1 soot = 1/8 in ≈ 3 mm
Full Chain
1 ft = 96 soot
12 × 8 = 96
012 345 678 91011 12 in ← 1 FOOT = 12 inches →
Where you see feet on site

Floor tile = 2 × 2 ft|Door height = 7 ft|Plywood = 8 × 4 ft|Brick ≈ 9 in|Room = 10 × 12 ft

Converting soot → inches → feet
ConversionRuleExample
soot → in÷ 84 soot = 4 ÷ 8 = 0.5 in
in → ft÷ 126 in = 6 ÷ 12 = 0.5 ft
soot → ft÷ 9648 soot = 48 ÷ 96 = 0.5 ft
ft → in× 122 ft = 24 in
in → soot× 81.5 in = 12 soot
ft → soot× 961 ft = 96 soot
On the calculator — 7 in 4 soot → ft
4 ÷ 8 = 0.5 in  →  7 + 0.5 = 7.5 in  →  7.5 ÷ 12 = 0.625 ft
Feet–Inch–Soot converter
=
5.625 ft

Practice Round — Feet, Inches & Soot

6 in = ? ft

Step 3 — Meter to Feet (m → ft)

Now we connect the two units. Only one number needs to be remembered:

Master Number
1 m = 3.28 ft
100 ÷ 30.48 = 3.28 · exact 3.28084
The Rule
meters × 3.28 = feet
Meter is the larger unit — the number increases
1 METER 1 ft2 ft3 ft 0.28 One meter contains 3 full feet plus 0.28 ft (≈ 3⅜ inches)
Common site conversions
Site itemMetersCalculationFeet
Room height3 m3 × 3.289.84 ft ≈ 10 ft
Plot side6 m6 × 3.2819.68 ft ≈ 20 ft
TMT bar12 m12 × 3.2839.37 ft ≈ 40 ft
Slab thickness0.15 m0.15 × 3.280.49 ft ≈ 6 in
Live converter — Meter → Feet
× 3.28 =
9.84 ft

3 m × 3.28084 = 9.84 ft

Practice Round — Meter to Feet

6 m = ? ft

Step 4 — Feet to Meter (ft → m)

The reverse journey — the dimension was given in feet, and the drawing or estimate needs it in meters.

Master Number
1 ft = 0.3048 m
30.48 cm — close to 30 cm for mental checks
The Rule
feet × 0.3048 = meters
Or feet ÷ 3.28 — the number decreases
Common site conversions
Site itemFeetCalculationMeters
Door height7 ft7 × 0.30482.13 m
Room side10 ft10 × 0.30483.048 m
Plywood sheet8 ft8 × 0.30482.44 m
Compound wall5 ft5 × 0.30481.52 m
Live converter — Feet → Meter
× 0.3048 =
3.048 m

10 ft × 0.3048 = 3.048 m

Practice Round — Feet to Meter

10 ft = ? m

Class 2 · Tape Reading

Reading a measuring tape — the engineer's first instrument

The upper edge of the tape carries inches and feet; the lower edge carries centimeters and millimeters. Learn to read a position precisely, then convert that reading between meters and feet.

Three rules for reading the tape
#RuleMeaning
1Upper edge — inches & feetEach number is one inch. Every 12th inch carries a red mark: 1F, 2F… meaning full feet. The smallest ticks are 1/8 inch (1 soot).
2Lower edge — cm & mmEach number is one centimeter; the small ticks between them are millimeters. Every full meter carries a red marker.
3State the reading in orderFull meters first, then centimeters, then millimeters — e.g. 1 m 23 cm 6 mm = 1.236 m.
Random Tape Drill Unlimited practice
READ HERE
4 ft + 1 m +
Class 3 · Area & Volume

Area and Volume — the foundation of every estimate

Tiles and paint are billed by area (sqft / m²); concrete, excavation and sand are billed by volume (cft / m³ / brass). Each shape below is taught with the site item where it actually appears — derive the formula, don't memorise it.

Area
1 m² = 10.76 sqft
Volume
1 m³ = 35.31 cft
Brass
1 brass = 100 cft
= 2.83 m³
Water
1 m³ = 1000 L
Part A — Area How much surface · m² / sqft

Governs tiling, painting, plastering, flooring and shuttering quantities.

a = 2 ft a VITRIFIED TILE 2×2 FT
Tile · Marble · Paver block

Square

Area = a × a = a²

Derivation: A square is simply a rectangle whose length and breadth are equal — so L × B reduces to a × a.

Site example: A 2 × 2 ft tile covers 4 sqft. A 120 sqft room needs 120 ÷ 4 = 30 tiles (32 with 5% wastage).
1sqft L = 12 ft B = 10 ft ROOM FLOOR (PLAN)
Room floor · Plot · Wall plaster

Rectangle

Area = L × B

Derivation: Divide the floor into 1 × 1 ft unit squares: 12 squares per row × 10 rows = 120 squares, i.e. 120 sqft. Multiplication is simply a faster way of counting unit squares.

Site example: A 12 × 10 ft room = 120 sqft = 120 × 0.093 = 11.15 m².
h base b GABLE WALL
Gable wall · Staircase side · Triangular plot

Triangle

Area = ½ × base × height

Derivation: Enclose the triangle in a rectangle of base b and height h (dashed outline). The triangle covers exactly half of that rectangle — hence the factor ½.

Site example: Gable wall with b = 4 m, h = 3 m → ½ × 4 × 3 = 6 m² of plaster area.
a = 3 m (top) b = 1 m h CANAL / DRAIN CROSS-SECTION
Canal · Road embankment · Irregular plot

Trapezium

Area = ½ × (a + b) × h

Derivation: Take the average of the two parallel sides, (a + b) ÷ 2. The trapezium behaves like a rectangle of that average width — so area = average width × height.

Site example: Drain with top 3 m, bottom 1 m, depth 1.5 m → ½ × (3 + 1) × 1.5 = 3 m² cross-section.
r d = 2r RCC COLUMN (PLAN)
Round column · Well · Manhole cover

Circle

Area = πr² = (π/4)d²

Derivation: π (≈ 3.1416) is the fixed ratio between any circle's circumference and its diameter. With radius r = d ÷ 2, the enclosed surface works out to πr².

Site example: Column with d = 450 mm = 0.45 m → r = 0.225 m → 3.1416 × 0.225² = 0.159 m².
Area in construction works Site sequence — footing to finishing

The same five shapes, applied to the real items you measure and bill on site — in the order they are built.

Step 1 · Footing shuttering

Footing Shuttering Area

A = 2 × (L + B) × D

Logic: The shutter covers the four vertical faces of the footing — that is the perimeter 2(L + B) multiplied by the footing depth D.

Site example: Footing 1.5 × 1.5 m, depth 0.45 m → 2 × (1.5 + 1.5) × 0.45 = 2.7 m² per footing. For 20 footings = 54 m² of shuttering.
Step 2 · Column shuttering

Column Shuttering Area

A = 2 × (a + b) × H

Logic: All four vertical faces of the column are shuttered — perimeter of the column cross-section 2(a + b) multiplied by the casting height H.

Site example: Column 230 × 450 mm, height 3 m → 2 × (0.23 + 0.45) × 3 = 4.08 m² per column.
Step 3 · Beam shuttering

Beam Shuttering Area

A = (B + 2D) × L

Logic: A beam is shuttered on three faces — the bottom (width B) and the two sides (depth D each). The top stays open for concreting.

Site example: Beam 230 wide × 450 deep, span 4 m → (0.23 + 2 × 0.45) × 4 = 4.52 m² per beam.
Step 4 · Slab shuttering

Slab Shuttering Area

A = L × B (soffit)

Logic: The shutter forms the underside (soffit) of the slab — a plain rectangle. Edge boards for slab thickness are minor and often added as perimeter × thickness.

Site example: Slab panel 6 × 3 m → 18 m² ≈ 194 sqft of plates and props.
Step 5 · Wall plaster

Wall Plaster Area

A = (L × H) − openings

Logic: Gross wall face minus doors and windows. Plaster on both faces means the net area is counted twice (internal + external).

Site example: Wall 4 × 3 m with a 2.1 × 0.9 m door → 12 − 1.89 = 10.11 m² per face → both faces = 20.22 m².
Step 6 · Flooring / Tiling

Flooring Area & Tile Count

A = L × B  →  Tiles = A ÷ tile area

Logic: Net carpet area of the room divided by the area of one tile, plus around 5% wastage for cutting.

Site example: Room 12 × 10 ft = 120 sqft → 120 ÷ 4 = 30 tiles of 2 × 2 ft → with 5% wastage order 32 tiles.
Area Calculator

Floor / Plaster Area

Area = 120 sqft = 11.15 m² · 2×2 tiles ≈ 30
Part B — Volume How much space is filled · m³ / cft / brass

Governs concrete, excavation, sand, aggregate and water quantities.

L = 20 ft t B = 10 ft RCC SLAB / EXCAVATION PIT
Slab concrete · Excavation · Brick

Cuboid

V = L × B × H

Derivation: Start with the base area (L × B) and extrude it through the height. Every solid follows the same principle: volume = base area × height.

Site example: Slab 20 × 10 ft, 0.5 ft thick → 20 × 10 × 0.5 = 100 cft = 1 brass = 2.83 m³ of concrete.
a = 150 mm a CONCRETE TEST CUBE
Cube test · Concrete quality

Cube

V = a × a × a = a³

Derivation: A cube is a cuboid with L = B = H, so the product of the three equal sides becomes a³.

Site example: Standard test cube, a = 150 mm = 0.15 m → 0.15³ = 0.003375 m³. Crushed at 7 and 28 days to verify concrete strength.
r h ROUND COLUMN / WATER TANK
Round column · Water tank · Pile

Cylinder

V = πr² × h

Derivation: The base is a circle of area πr². Extruding it through the height h gives πr²h — base area × height once again.

Site example: Column d = 0.45 m, h = 3 m → 0.477 m³. Tank r = 1 m, h = 1 m → 3.14 m³ = 3,140 litres.
h r SAND / AGGREGATE HEAP
Sand heap · Aggregate stock · Hopper

Cone

V = ⅓ × πr² × h

Derivation: A cone holds exactly one-third of the cylinder that shares its base and height — hence the factor ⅓. This is also why loose sand naturally stockpiles in a conical shape.

Site example: Sand heap d = 4 m, h = 1.5 m → ⅓ × 3.1416 × 2² × 1.5 = 6.28 m³ ≈ 2.2 brass.
Volume in construction works Site sequence — excavation to brickwork

The same solids, applied to the works you actually bill in m³ / cft / brass — in the order they happen on site.

Step 1 · Excavation

Excavation Volume

V = L × B × D

Logic: Pit size is taken 150–300 mm larger than the footing on all sides as working space. Billed in cum (m³) or cft.

Site example: Pit 1.8 × 1.8 m, depth 1.5 m → 1.8 × 1.8 × 1.5 = 4.86 m³ per pit → 20 pits = 97.2 m³.
Step 2 · PCC

PCC Volume

V = L × B × t

Logic: A thin plain-concrete bed (usually 75–100 mm) below the footing gives a clean, level base. Same cuboid rule with a small thickness.

Site example: PCC 1.8 × 1.8 m, 100 mm thick → 1.8 × 1.8 × 0.1 = 0.324 m³ per pit.
Step 3 · Footing concrete

Footing Concrete Volume

V = L × B × D

Logic: The footing block is a cuboid cast inside the box formwork. Stepped or sloped footings are split into simple blocks and added.

Site example: Footing 1.5 × 1.5 m, depth 0.45 m → 1.01 m³ per footing → 20 footings ≈ 20.25 m³ of concrete.
Step 4 · Column concrete

Column Concrete Volume

V = a × b × H

Logic: Cross-section area of the column multiplied by the casting height — floor to beam bottom. Round columns use πr² × H instead.

Site example: Column 230 × 450 mm, H = 3 m → 0.23 × 0.45 × 3 = 0.31 m³ per column → 20 columns = 6.2 m³.
Step 5 · Beam concrete

Beam Concrete Volume

V = B × D × L

Logic: Beam cross-section (width × depth) multiplied by the clear span between columns. When the slab is cast together, beam depth is taken below the slab.

Site example: Beam 230 × 450 mm, span 4 m → 0.23 × 0.45 × 4 = 0.41 m³ per beam.
Step 6 · Slab concrete

Slab Concrete Volume

V = L × B × t

Logic: Plan area of the slab multiplied by its thickness (typically 100–150 mm). This is the single biggest concrete pour of a floor.

Site example: Slab 6 × 3 m, 125 mm thick → 6 × 3 × 0.125 = 2.25 m³ ≈ 79.4 cft ≈ 0.8 brass.
Step 7 · Brickwork

Brickwork Volume

V = L × H × t

Logic: Wall length × height × wall thickness (230 mm for a full-brick wall, 115 mm for half-brick). One m³ of brickwork needs about 500 bricks with mortar.

Site example: Wall 3 × 3 m, 230 mm thick → 3 × 3 × 0.23 = 2.07 m³ → 2.07 × 500 ≈ 1,035 bricks.
Volume Calculator

Slab / Concrete Volume

Volume = 100 cft = 1.00 brass = 2.83 m³